(x-y)^2 -8(x-y)+16
請詳細列明所有步驟。
f.2因式分解(3)
2006-10-23 4:36 am
回答 (5)
2006-10-23 4:54 am
✔ 最佳答案
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2006-10-23 6:23 am
(x-y)²-8(x-y)+16
=(x-y)²-2(4)(x-y)+4²
=[(x-y)-4]²
=(x-y-4)²
=(x-y)²-2(4)(x-y)+4²
=[(x-y)-4]²
=(x-y-4)²
2006-10-23 4:46 am
=(x-y-4)(x-y-4)
用2次方程的做法
設(x-y)= x
(x)^2 -8(x)+16
=(x-4)(x-4)
再代(x-y)入x
=(x-y-4)(x-y-4)
用2次方程的做法
設(x-y)= x
(x)^2 -8(x)+16
=(x-4)(x-4)
再代(x-y)入x
=(x-y-4)(x-y-4)
2006-10-23 4:44 am
(x-y-4)^2lo
十字相乘呀天才!!!!!!!!!!!!!!!!!!!!!
x-y \/ -4
x-y /\ -4
-8(x-y)
十字相乘呀天才!!!!!!!!!!!!!!!!!!!!!
x-y \/ -4
x-y /\ -4
-8(x-y)
2006-10-23 4:40 am
(x-y)²-8(x-y)+16
=(x-y)²-2(4)(x-y)+4²
=[(x-y)-4]²
=(x-y-4)²
=(x-y)²-2(4)(x-y)+4²
=[(x-y)-4]²
=(x-y-4)²
參考: Calculation
收錄日期: 2021-04-12 21:51:45
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061022000051KK05342