factorize ( very 急)

2006-10-23 1:12 am
(3/x-y) + ( 2/y-x)

回答 (2)

2006-10-23 1:15 am
✔ 最佳答案
factorize ( very 急)
(3/x-y) + ( 2/y-x)
(3/x-y)=-3/(y-x)
-3/(y-x)+ ( 2/y-x)
=-1/(y-x)
=1/(x-y)


questions of identities and factorize
1) 你係唔係想打 a^2-(a-b)^2a^2-(a-b)^2= [a - (a-b)] [a + (a-b)]= (a-a+b) (a+a-b)= b(2a-b)2) 2(a^2 + 6a + 9)= 2(a+3)^23) C4) (x^2+8x+16)-16y^2= (x+4)^2 - (4y
分類: 中小學校 時間:2006/09/28
factorize
4(ab-xy)^2-(a^2+b^2-x^2-y^2)^2={2(ab-xy)}^2-(a^2+b^2-x^2-y^2)^2={2(ab-xy)+a^2+b^2-x^2-y^2}{2(ab-xy)-(a^2+b^2-x^2-y^2)}=====use a^2-b^2=(a+b)(a-b)=(2ab
分類: 數學 時間:2006/09/21
factorize x^3 - 3ax + 2a^3 你話易定難?
唔會撞唔中啦好似這條0甘代個a就看到x^3 - 3ax + 2a^3=0x-a是因子有冇必無殺技?某層次上有的因為所有嘗試的數都會是2a^3的因子所以正常會試1,a,-a,2a,-2a,a^2,-a^2.........等﹐一定試到個對的慢慢試一定試到(除非條題目玩你,要你用1/17a個0的就無話可
分類: 數學 時間:2006/09/22
一條factorize問題
(162)(X^4)-(2)(Y^4)=2[(81)(X^4)-(Y^4)]=2[(9X^2)^2-(Y^2)^2]= 2[(9X^2-Y^2)(9X^2+Y^2)] since (A^2-B^2)=(A-B)(A+B)= 2(3X-Y)(3X+Y)(9X^2+Y^2)
分類: 數學 時間:2006/09/08
polynomials (factorize)
Answer : g( x ) = ( x + 1 )( x - 2 )( x + 3 ) Solutions : g( x ) = x³ + 2x² - 5x - 6 Since g( - 1 ) = ( - 1 )³ + 2( - 1 )² - 5( - 1 ) - 6 = 0, By
分類: 數學 時間:2006/08/19
factorize a formula f(?x..?y) (?x..?y)
** (x+y)(x-y) = x^2 - y^2Solution: y^2-5y+10x-4x^2 =-4x^2+y^2-5y+10x <---- Rearrange terms=(y+2x)(y-2x)-5(y-2x) <---- Takin
分類: 數學 時間:2006/05/20
5(3m-n)^2-(n-3m),,plx factorize!
5(3m-n)^2-(n-3m),,plx factorize!
分類: 數學 時間:2006/10/16
factorize two questions
a)t^2 + (t+3)^3 - 17= t^2 + [t^3 + 3(t^2)(3) + 3(t)(9) + 27] -17= t^3 + 10t^2 + 27t + 10= t^3 + 10t^2 + 25t + 2t + 10= t(t^2 + 10t + 25) + 2(t+5)= t(t
分類: 數學 時間:2006/05/27
factorize
Let me solve them.x³ - 7x + 6Method:1.You use this formulax³ + 27=(x+3)(x²-3x+9)2.Sub. in question x³ - 7x + 6x³ - 7x + 6=x³ - 7x + 6 - 27+ 27=x³ - 7x
分類: 數學 時間:2006/10/17
factorized
Factorized the following expression:(4a-b)(4a-b)=?
分類: 中小學校 時間:2006/10/12
2006-10-23 1:14 am
(3/x-y) + (2/y-x)
=(3/x-y) - (2/x-y)
=(3-2)/(x-y)
=1/(x-y)


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