1)
(20+2x)(15+2x)-(20*15)=246
300+70x+4x^2-546=0
4x^2+70x-246=0
(2x+41)(2x-6)=0
x=-41/2 or x=3
2)
3x(x-12)=0
x=0 or x=12
(ax+b)(cx+d)......(kx+n)=0
There must be at least one binomials ax+b,cx+d......kx+n is equal to 0
Therefore ax+b=0 or cx+d=0...... or kx+n=0
x=-b/a or x=-d/c ...... or x=-n/k