Show that the function f(x)=(2x^2+3)^3/2 is decreasing for x < 0 and increasing for x > 0
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請問應該點樣計decreasing for x 0,請加以解釋THX
2006-10-22 7:00 pm
回答 (1)
2006-10-22 8:09 pm
✔ 最佳答案
f(x) = (2x^2 +3)^(3/2)f’(x) = (3/2) * (2x^2 +3)^(1/2) * (4x)
For x less than 0,
f’(x) is negative,
i.e. The slope of y = f(x) is negative
Hence, f(x) is decreasing for x less than 0.
For x greater than 0,
f’(x) is positve,
i.e. The slope of y = f(x) is positive
Hence, f(x) is increasing for x greater than 0.’
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https://hk.answers.yahoo.com/question/index?qid=20061022000051KK01340