1. Factorize x的3次 - 7x + 36
2. Factorize x的3次 + 4x的2次 - 11x - 30
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f.3 maths
2006-10-22 6:22 pm
回答 (2)
2006-10-24 1:44 am
✔ 最佳答案
1)x^3 - 7x + 36
=x^3 - 16x + 9x - 36 + 4x^2 - 4x^2
=x^3 + 4x^2 + 9x - 4x^2 - 16x - 36
=x(x^2 + 4x + 9)-4(x^2 + 4x + 9)
=(x-4)(x^2 + 4x + 9)
2)
x^3 + 4x^2 - 11x - 30
=x^3 + 7x^2 + 10x - 3x^2 - 21x - 30
=x(x^2 + 7x + 10)-3(x^2 + 7x + 10)
=(x-3)(x^2 + 7x + 10)
=(x-3)(x+2)(x+5)
2006-10-22 6:33 pm
(1). x^3 - 7x + 36
= (x - 4) (x^2 + 4x + 9)
(2). x^3 + 4x^2 - 11x - 30
= (x - 3) (x^2 + 7x + 10)
= (x - 3) (x + 2) (x + 5)
= (x - 4) (x^2 + 4x + 9)
(2). x^3 + 4x^2 - 11x - 30
= (x - 3) (x^2 + 7x + 10)
= (x - 3) (x + 2) (x + 5)
收錄日期: 2021-04-23 13:21:02
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