在下列每題的4個數中,隨意使用+ , - , X , ÷ , 括號,對4個數進行運算,
列出一個算式,使計算結果等於24
(1)6,8,12,13
(2)4,8,9,12
(3)5,6,9,10
(4)2,6,9,9
(5)6,7,8,11
(6)7,12,12,13
(7)2,2,2,11
(8)2,4,10,11
(9)3,5,6,10
(10)4,7,10,12
(11)2,4,6,11
(12)3,6,9,10
(13)4,7,12,12
麻煩你們了,我真的想了很久也想不到!
合24的難題
2006-10-21 11:13 pm
回答 (4)
2006-10-22 1:01 am
✔ 最佳答案
(1) (2) 8x9÷12x4
(3) (9-10+5)x6
(4) (9+9-6)x2
(5) ([8+7-11)x6
(6). [12÷(13-7)]x12
(7) 2x[11+(2÷2)]
(8) 11x4-2x10
(9) (10÷5+6)x3
(10) (10+4)÷7x12
(11) 11x2+6-4
(12) (10-9+3)x6
(13) (7-12÷12)x4
2007-01-11 8:21 am
(1) 不能
2006-10-23 4:53 am
(1) 諗極都諗唔到 sorry^^
(2) 8x9÷12x4
(3) (9-10+5)x6
(4) (9+9-6)x2
(5) ([8+7-11)x6
(6). [12÷(13-7)]x12
(7) 2x[11+(2÷2)]
(8) 11x4-2x10
(9) (10÷5+6)x3
(10) (10+4)÷7x12
(11) 11x2+6-4
(12) (10-9+3)x6
(13) (7-12÷12)x4
希望幫到你^^
(2) 8x9÷12x4
(3) (9-10+5)x6
(4) (9+9-6)x2
(5) ([8+7-11)x6
(6). [12÷(13-7)]x12
(7) 2x[11+(2÷2)]
(8) 11x4-2x10
(9) (10÷5+6)x3
(10) (10+4)÷7x12
(11) 11x2+6-4
(12) (10-9+3)x6
(13) (7-12÷12)x4
希望幫到你^^
2006-10-21 11:28 pm
我幫你8條la
3).[9-(10-5)]x6
4).(9+9-6)x2
5).[8-(11-7)]x6
6).[12÷(13-7)]x12
7).2x[11+(2÷2)]
9).(10÷5+6)x3
12).(10-9+3)x6
13.)(7-12÷12)x4
其它幫唔到,
very sorry
試下:
2x12
3x8
4x6
la!
加油!
2006-10-21 15:31:56 補充：
10. [(10+4)÷7]x12
2006-10-21 15:34:48 補充：
8. (11-10÷2)x4
2006-10-23 20:06:10 補充：
其實第1題係不可以的呀!
3).[9-(10-5)]x6
4).(9+9-6)x2
5).[8-(11-7)]x6
6).[12÷(13-7)]x12
7).2x[11+(2÷2)]
9).(10÷5+6)x3
12).(10-9+3)x6
13.)(7-12÷12)x4
其它幫唔到,
very sorry
試下:
2x12
3x8
4x6
la!
加油!
2006-10-21 15:31:56 補充：
10. [(10+4)÷7]x12
2006-10-21 15:34:48 補充：
8. (11-10÷2)x4
2006-10-23 20:06:10 補充：
其實第1題係不可以的呀!
收錄日期: 2021-04-12 23:04:35
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061021000051KK02935