Kathy is 18% shorter than Jason, and Timothy is 20% taller than Kathy. Compare the heights of Jason and Timothy, who is taller? By what percentage?
請列式!!!!!
Percentages question (maths)
2006-10-21 9:16 pm
回答 (3)
2006-10-21 9:26 pm
✔ 最佳答案
Let x be the height of Jason.The height of Timothy is x(1-18%)(1+20%) = 98.4%x
Jason is taller than Timothy 1 - 98.4% = 1.6%
2006-10-21 11:48 pm
Let Timothy’s height to y
Kathy’s height = y×(1﹣20%) = 0.8y
Jason’s height = 0.8y×(1+18%) = 0.944y
∴Timothy is taller than Jason
Timothy is taller than Jason
=(y﹣0.944y) / 0.944y×100%
=y(1﹣0.944) / 0.944y×100%
=5.93%
Jason is shorter thanTimothy
=(y﹣0.944) / y×100%
=y(1﹣0.944) / y×100%
=5.6%
Kathy’s height = y×(1﹣20%) = 0.8y
Jason’s height = 0.8y×(1+18%) = 0.944y
∴Timothy is taller than Jason
Timothy is taller than Jason
=(y﹣0.944y) / 0.944y×100%
=y(1﹣0.944) / 0.944y×100%
=5.93%
Jason is shorter thanTimothy
=(y﹣0.944) / y×100%
=y(1﹣0.944) / y×100%
=5.6%
參考: The form two maths book
2006-10-21 9:26 pm
Let height of kathy=10
Let height of jason= H
H*(1-0.18)=10
H=12.195
Let height of Timothy=10*1.2=12
therefore Jason is higher.
Let height of jason= H
H*(1-0.18)=10
H=12.195
Let height of Timothy=10*1.2=12
therefore Jason is higher.
參考: me
收錄日期: 2021-04-23 19:26:44
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061021000051KK02143