John and Mary play a dice game.John tosses a dice and scores the double of the number shown.Mary tosses two dice and scores the sum of the numbers shown.whoever scores more will win.Find the probability for
a.)john to win
b.)Mary to win
c.)a tie game
probability question!!
2006-10-21 1:59 am
回答 (3)
2006-10-21 2:11 am
✔ 最佳答案
勝負機會一樣Mary 擲2 粒點數的出現次數
點數
出現次數
2
1
3
2
4
3
5
4
6
5
7
6
8
5
9
4
10
3
11
2
12
1
john 擲的點數，勝和負的機會
骰子
點數x2
勝
和
負
1
2
35
1
0
2
4
30
3
3
3
6
21
5
10
4
8
10
5
21
5
10
3
3
30
6
12
0
1
35
總結
99
18
99
若以216局計，每有各勝99次，點數相同有18次，
a.)john to win
的概率為 99/216 = 11/24
b.)Mary to win
的概率為 99/216 = 11/24
c.)a tie game
18/216= 1/12
2006-10-21 3:08 am
a.)john to win
的概率為 99/216 = 11/24
b.)Mary to win
的概率為 99/216 = 11/24
c.)a tie game
18/216= 1/12
的概率為 99/216 = 11/24
b.)Mary to win
的概率為 99/216 = 11/24
c.)a tie game
18/216= 1/12
2006-10-21 2:11 am
John has equal chance of getting 2, 4, 6, 8, 10 and 12.
Mary has 1/36 chance of getting 2, 2/36 for 3, 3/36 for 4... 6/36 for 7... 1/36 for 12.
a) 1/6 * (35+30+21+10+3)/36
= 99/216
= 11/24
b) 1/6 * (35+30+21+10+3)/36
= 99/216
= 11/24
c) 1/6 * (1+3+5+5+3+1)/36
= 18/216
= 2/24 or 1/12 //
Mary has 1/36 chance of getting 2, 2/36 for 3, 3/36 for 4... 6/36 for 7... 1/36 for 12.
a) 1/6 * (35+30+21+10+3)/36
= 99/216
= 11/24
b) 1/6 * (35+30+21+10+3)/36
= 99/216
= 11/24
c) 1/6 * (1+3+5+5+3+1)/36
= 18/216
= 2/24 or 1/12 //
收錄日期: 2021-04-12 19:06:51
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