formulae

👨🏻‍🏫 學術台數學

Lan

2006-10-20 5:39 am

1. 2- (4-a / 6a)

2. 2x / x(x-1) + 5 / -3x

回答 (3)

Joseph

2006-10-20 5:52 am

✔ 最佳答案

1. 2- (4-a / 6a)
= (12a-4+a)/6a
= (13a-4)/6a

2. 2x / x(x-1) + 5 / -3x
= 2/(x-1) - 5/3x
= (6x-5x+5)/3x(x-1)
= (x+5)/3x(x-1)

參考: 自己

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kings

2006-10-22 12:29 am

GOOD!!! 加油!!!

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bfaifaiwong

2006-10-20 5:47 am

1. 2- (4-a / 6a)
= (12a - 4 + a)/6a
= (13a - 4)/6a

2. 2x / x(x-1) + 5 / -3x
= (6x - 5x + 5) / 3x(x-1)
= (x + 5) / 3x(x-1) or (x+5) / (3x^2 - 3x)

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