formulae
1. 2- (4-a / 6a)
2. 2x / x(x-1) + 5 / -3x
回答 (3)
✔ 最佳答案
1. 2- (4-a / 6a)
= (12a-4+a)/6a
= (13a-4)/6a
2. 2x / x(x-1) + 5 / -3x
= 2/(x-1) - 5/3x
= (6x-5x+5)/3x(x-1)
= (x+5)/3x(x-1)
參考: 自己
1. 2- (4-a / 6a)
= (12a - 4 + a)/6a
= (13a - 4)/6a
2. 2x / x(x-1) + 5 / -3x
= (6x - 5x + 5) / 3x(x-1)
= (x + 5) / 3x(x-1) or (x+5) / (3x^2 - 3x)
收錄日期: 2021-04-12 22:30:49
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