我要長笞16=-8(5p+8)和5(7+3q)+12=2

2006-10-20 4:41 am
我要長笞16=-8(5p+8)和5(7+3q)+12=2

回答 (6)

2006-10-20 4:46 am
✔ 最佳答案
16=-8(5p+8)
-2=5p+8
-10=5p
p=-2

5(7+3q)+12=2
5(7+3q)= -10
7+3q = -2
3q =-9
q=-3
參考: 自己計
2006-10-20 5:09 am
16 = -40p (-64)
-40p = -64 -16
p = -80/40
p = 2


35 +15q +12= 2
15q= 2-35-12
q= -45/15
q= -3
2006-10-20 4:50 am
16=-8(5p+8)
16=-40p-64
80=-40p
-2=p



5(7+3q)+12=2
35+15q+12=2
47+15q=2
15q=2-47
15q=-45
q=-3
2006-10-20 4:48 am
16=-8(5p+8)
16=-40p-64
40p=-64-16
40p=-80
p=-2

5(7+3q) +12 = 2
35 +15q+12 = 2
15q = -45
q = -3
參考: me
2006-10-20 4:46 am
16=-8(5p+8)
16=-40p-16





5(7+3q)+12=2
35+15q+12=2
47+15q=2
2006-10-20 4:46 am
16= -8(5p+8)
16=-40p-64
16+64=-40p
80=-40p
p=-2

5(7+3q)+12=2
35+15q+12=2
47+15q=2
15q= -45
q= -3
參考: me


收錄日期: 2021-04-12 20:57:55
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