Find the range of 1/(2x^2-5x-42).
x is a real no.
Quadratic equation
2006-10-20 1:07 am
回答 (1)
2006-10-20 1:20 am
✔ 最佳答案
1/(2x^2-5x-42)=1/(2x+7)(x-6)
Since 1/0 would be undefined,
thus, x can be any real no. except x=6 or x=-7/2
收錄日期: 2021-04-13 00:26:53
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061019000051KK02231