1, 1/w = (r+1/s)tsd``````````````````change the subject is [s]
2,S=n/2[2a+(n-1)d]`````````````````change the subject is [a]
need the steps!!!!!
thz!!!!!!!!
F.2 MATHZ` [subject of the formula]
2006-10-19 7:42 am
回答 (3)
2006-10-19 7:00 pm
✔ 最佳答案
Solution:(1)
1/w = (r+1/s)tsd
1/ tsdw = (sr+1)/sAssume s≠0
1/ tdw = sr+1
1/ tdw - 1= sr
sr = 1/ tdw – 1
s = 1/r (1/ tdw – 1)
(2)
S=n/2[2a+ (n-1) d]
2S=n [2a+ (n-1) d]
2S= 2an+ n (n-1) d
2an = 2S - n (n-1) d
a = [2S - n (n-1) d] / 2n
a = S/n – [(n-1) d]/2
2006-10-19 5:12 pm
1. 1 / w = [r + (1 / s)] tsd
1 / w= rtsd + (1 / s)tsd
1 / w = rtsd + td
rtsd = (1 / w) - td
rtsd = (1 - wtd) / w
s = (1 - wtd) / wrtd
2. S = (n / 2)[2a + (n - 1)d]
2S = n[2a + (n - 1)d]
2S / n = [2a + (n - 1)d]
2a = (2S / n) - (n - 1)d
a = [(2S / n) - (n - 1)d] / 2
1 / w= rtsd + (1 / s)tsd
1 / w = rtsd + td
rtsd = (1 / w) - td
rtsd = (1 - wtd) / w
s = (1 - wtd) / wrtd
2. S = (n / 2)[2a + (n - 1)d]
2S = n[2a + (n - 1)d]
2S / n = [2a + (n - 1)d]
2a = (2S / n) - (n - 1)d
a = [(2S / n) - (n - 1)d] / 2
2006-10-19 7:47 am
1. 1 / w = [r + (1 / s)] tsd
1 / w= rtsd + (1 / s)tsd
1 / w = rtsd + td
rtsd = (1 / w) - td
rtsd = (1 - td) / w
s = (1 - td) / wrtd
2. S = (n / 2)[2a + (n - 1)d]
2S = n[2a + (n - 1)d]
2S / n = [2a + (n - 1)d]
2a = (2S / n) - (n - 1)d
a = [(2S / n) - (n - 1)d] / 2
1 / w= rtsd + (1 / s)tsd
1 / w = rtsd + td
rtsd = (1 / w) - td
rtsd = (1 - td) / w
s = (1 - td) / wrtd
2. S = (n / 2)[2a + (n - 1)d]
2S = n[2a + (n - 1)d]
2S / n = [2a + (n - 1)d]
2a = (2S / n) - (n - 1)d
a = [(2S / n) - (n - 1)d] / 2
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