求x:(x-1)=(x+2):3中的x.

2006-10-19 3:47 am
求x:(x-1)=(x+2):3中的x.

回答 (6)

2006-10-19 3:58 am
✔ 最佳答案
x / (x - 1) = (x + 2) / 3
3x = (x - 1)(x + 2)
3x = x^2 - x + 2x - 2
x^2 - 2x - 2 = 0
x^2 - 2x + 1 - 3 = 0
(x - 1)^2 = 3
x - 1 = √3 or x - 1 = -√3
x = 1 + √3 or x = 1 - √3
2006-10-20 4:46 am
x / (x - 1) = (x + 2) / 3
3x = (x - 1)(x + 2)
3x = x^2 - x + 2x - 2
x^2 - 2x - 2 = 0
x^2 - 2x + 1 - 3 = 0
(x - 1)^2 = 3
x - 1 = √3 or x - 1 = -√3
x = 1 + √3 or x = 1 - √3
2006-10-19 3:58 am
你係咪抄錯題目呀??呢條題目係計唔倒既...冇數係
x=x+3/x-3=x
2006-10-19 3:58 am
你條數冇解啵~
除非絕對左個(x-1), 咁就有解
解: -x+1=x+2
2x=-1
x=-1/2
2006-10-19 3:52 am
(x-1)=(x+2)
x=x+2+1
x=x-3

無可能有正確答案
無論x是0,1,2,3,4,5,都無可能。
2006-10-19 3:52 am
你係咪問(x-1)=(x+2)當中x=咩??
如果係,咁我可以答你:
e條數係冇可能計到架


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