兩個連續奇數的積是63, 求這兩個數,
回答 (3)
2006-10-19 5:36 pm
設x為小的奇數，(x + 2)為大的奇數
x(x + 2) = 63
x^2 + 2x - 63 = 0
(x - 7)(x + 9) = 0
x = 7 or x = -9(rejected)
因為小的奇數等於7，所以大的奇數等於9。
x(x + 2) = 63
x^2 + 2x - 63 = 0
(x - 7)(x + 9) = 0
x = 7 or x = -9(rejected)
因為小的奇數等於7，所以大的奇數等於9。
2006-10-19 5:11 am
兩個連續奇數是7和9
2006-10-19 4:18 am
let x be one of the smaller number
x+(x+1)=63
2X=63-1
X=62/2
X =31
the other number is 32
x+(x+1)=63
2X=63-1
X=62/2
X =31
the other number is 32
參考: myself
收錄日期: 2021-04-12 22:41:00
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