An oxide element X has the formula X2O3.10.2g of this oxide contains 5.4g of X.what is relative atomicmass of X?(Relative atomic mass :O=16.0
A.12 B.18.0 C.27.0 D.36.0
chemistry (急)10點
2006-10-18 5:59 am
回答 (2)
2006-10-19 2:55 am
✔ 最佳答案
Mass of oxygen in the compound = 10.2 - 5.4 = 4.8 gRelative atomic mass of oxygen= 16.0
No. of mole of oxygen = 4.8 / 16.0 = 0.3 mol
No. of mole of X = 0.3 X 2/3 = 0.2 mol
Mass of X in the compound = 5.4 g
So, relative atomic mass of X = 5.4 / 0.2 = 27.0
So, the answer is C. 27.0
2006-10-18 6:08 am
Mass of oxygen in compound = 10.2-5.4=4.8g
no. of mole of oxygen = mass/molar mass= 4.8/16=0.3mol
From the formla X2O3,
the mole ratio of X to O is 2:3
so, no. of mole of X = 0.2mole
Relative atomic mass of X = 5.4/0.2 = 27
The answer is C
no. of mole of oxygen = mass/molar mass= 4.8/16=0.3mol
From the formla X2O3,
the mole ratio of X to O is 2:3
so, no. of mole of X = 0.2mole
Relative atomic mass of X = 5.4/0.2 = 27
The answer is C
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