1. -3(2d+e)(e-2d)
2. c(4d-3e)(-4d-3e)
列式作答
math------expand
2006-10-18 4:55 am
回答 (2)
2006-10-18 5:56 am
1.....-3(2d+e)(e-2d)
....=(-6d-3e)(e-2d)
....=-6de+12d*2-3e*2+6de
....=12d*2-3e*2
2.....c(4d-3e)(-4d-3e)
.....=(4cd-3ce)(-4d-3e)
.....=-16cd*2-12cde+12cde+9ce*2
.....=-16cd*2+9ce*2
*2=二次方
....=(-6d-3e)(e-2d)
....=-6de+12d*2-3e*2+6de
....=12d*2-3e*2
2.....c(4d-3e)(-4d-3e)
.....=(4cd-3ce)(-4d-3e)
.....=-16cd*2-12cde+12cde+9ce*2
.....=-16cd*2+9ce*2
*2=二次方
2006-10-18 5:14 am
1. -3(2d+e)(e-2d)
=[(-3)(2d+e)](e+2d)
=(-6d-3e)(e+2d)
=e(-6d-3e)+2d(-6d-3e)
=-6de-3e^2-12d^2-6de
=3e^2-12de-12d^2
2. c(4d-3e)(-4d-3e)
=[c(4d-3e)](-4d-3e)
=(4cd-3ce)(-4d-3e)
=4cd(-4d-3e)-3ce(-4d-3e)
=-16cd^2-12cde+12cde+9ce^2
=-16cd^2+9ce^2
2006-10-17 21:15:26 補充：
^2=2次方
=[(-3)(2d+e)](e+2d)
=(-6d-3e)(e+2d)
=e(-6d-3e)+2d(-6d-3e)
=-6de-3e^2-12d^2-6de
=3e^2-12de-12d^2
2. c(4d-3e)(-4d-3e)
=[c(4d-3e)](-4d-3e)
=(4cd-3ce)(-4d-3e)
=4cd(-4d-3e)-3ce(-4d-3e)
=-16cd^2-12cde+12cde+9ce^2
=-16cd^2+9ce^2
2006-10-17 21:15:26 補充：
^2=2次方
參考: me
收錄日期: 2021-04-13 00:54:38
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061017000051KK04073