1.7k-(9k-16)=14-(19-k)
2.2【p-2(p+1)】-1=8p+25
更新1:
加多一題: 3.7+2e=9e-14-6e
兩條中一程度的代數加減題目?(明日要交,急)十分
回答 (4)
2006-10-18 4:55 am
✔ 最佳答案
1.7k-(9k-16)=14-(19-k)7k-9k+16=14-19+k
-2k-k =14-19-16
-3k =-21
k = 7
2.2【p-2(p+1)】-1=8p+25
2【p-2p-2】-1 =8p+25
2p-4p-4-1 =8p+25
-2p-5 =8p+25
-10p =25+5
p =-3
2006-10-26 12:05 am
1.7k-(9k-16)=14-(19-k)
7k-9k+16=14-19+k
7k-9k-k=14-19-16
-3k=-21
k=-21/-3
k=7
2.2【p-2(p+1)】-1=8p+25
2【p-2p-2】-1=8p+25
2p-4p-4-1=8p+25
2p-4p-8p=25+4+1
-10p=30
p=30/-10
p=-3
3.7+2e=9e-14-6e
2e-9e+6e=-14-7
-e=-21
e=-21/-1
e=21
7k-9k+16=14-19+k
7k-9k-k=14-19-16
-3k=-21
k=-21/-3
k=7
2.2【p-2(p+1)】-1=8p+25
2【p-2p-2】-1=8p+25
2p-4p-4-1=8p+25
2p-4p-8p=25+4+1
-10p=30
p=30/-10
p=-3
3.7+2e=9e-14-6e
2e-9e+6e=-14-7
-e=-21
e=-21/-1
e=21
2006-10-18 5:00 am
1. 7k-9k+16=14-19+k
7k-9k-k=14-19-16
-3k=-21
k=7
2. 2(p-2p-2)-1=8p+25
2p-4p-4-1=8p+25
2p-4p-8p=25+4+1
-10p=30
p=-3
7k-9k-k=14-19-16
-3k=-21
k=7
2. 2(p-2p-2)-1=8p+25
2p-4p-4-1=8p+25
2p-4p-8p=25+4+1
-10p=30
p=-3
2006-10-18 4:56 am
7k-(9k-16)=14(19-k)
7k-9k+16=14(19-k)
-2k+16 =14(19-k)
-2k+16 =266-k
16-266 =2k-k
-250 =k
2[p-2(p+1)]-1=8p+25
Sorry ! 我唔知
Because I am a F.1 student . just sme at u
7k-9k+16=14(19-k)
-2k+16 =14(19-k)
-2k+16 =266-k
16-266 =2k-k
-250 =k
2[p-2(p+1)]-1=8p+25
Sorry ! 我唔知
Because I am a F.1 student . just sme at u
參考: 我
收錄日期: 2021-05-03 08:50:41
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