inequalities~~~a...maths

2006-10-18 4:03 am
please solve the following inequality~ thx

(x-2)/2 is less than (3x+4)/3 is less than (6x-4)/6







(((becoz i cannot type the symbol of is less than,,, so i use words instead,,,hope u will understand)))

回答 (3)

2006-10-18 6:30 pm
(x-2)/2 is less than (3x+4)/3:
(x - 2) / 2 < (3x + 4) / 3
3(x - 2) < 2(3x + 4)
3x - 6 < 6x + 8
3x - 6x < 8 + 6
-3x < 14
x > 14 / (-3)

(3x+4)/3 is less than (6x-4)/6:
3 < (6x - 4) / 6
3 < (3x- 2)/ 3
9 < 3x - 2
11 < 3x
3x > 11
x > 11 / 3
2006-10-18 7:56 am
(x-2)/2<(3x+4)/3<(6x-4)/6 all terms times 6
3x-6 < 6x+8 < 6x-4
i.e. 3x-6 < 6x+8 and 6x+8 < 6x-4
-14 < 3x and 8 < -4

Bcos 8 < -4 is impossible, so there is no solution for the inequalities above.
2006-10-18 4:10 am
(x-2)/2<(3x+4)/3
3(x-2)<2(3x+4)
3x-6<6x+8
-3x<14
x>14/3

3<(6x-4)/6
3<(3x-2)/3
9<3x-2
-3x<-11
x>11/3
參考: Calculation


收錄日期: 2021-04-12 22:40:56
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20061017000051KK03634

檢視 Wayback Machine 備份