有關Matrix的問題

2006-10-17 11:54 pm

Given the solution of a system of linear equations:
x1=6k+s-t+2 , x2=k , x3=-5s+3t-1 , x4=s , x5=-8-5t , x6=t

應該如何設equations呢?(我只知總共有六條)

回答 (1)

2006-10-19 10:52 am

✔ 最佳答案

x1=6k+s-t+2 , x2=k , x3=-5s+3t-1 , x4=s , x5=-8-5t , x6=t

x1=6x2+x4-x6+2
x3=-5x4+3x6-1
x5=-8-5x6
that is
x1-6x2-x4+x6-2=0
x3+5x4-3x6+1=0
x5+5x6+8=0

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