１０分 !!幾條因式分解問題

12x^2 + 12x + 3
= 3(4x^2 + 4x + 1)
= 3[(2x)^2 + 2(2x)(1) + (1)^2]
= 3(2x + 1)^2
18a^2 + 48ab + 32b^2
= 2[9a^2 + 24ab + 16b^2]
= 2[(3a)^2 + 2(3a)(4b) + (4b)^2]
= 2(3a + 4b)^2
(x - y)^2 - y^2
= [x - y + y][x - y - y]
= x(x - 2y)

咩的^2 = [2次方]

12x[2次方]+12x+3= 144+12x+3
　　　　　　　　 =147+12x


(x-y)[2次方]-y[2次方] =(x-y)(x-y) - y^2
=x^2 - xy - yx + y^2 - y^2
=x^2 - 2xy

2006-10-16 22:13:07 補充：
睇唔到x12x[2次方]+12x+3=3(4x^2+4x+1) =3[(2x)^2+(2)(2x)+(1)^2] =3(2x+1)^2 補充的...18a[2次方]+48ab+32b[2次方]= 2(9a^2+24ab+16a^2)=2[(3a)^2+2(3a)(4b)+(4b)^2]=2(3a+4b)^2

12x12x2X+12X+3

???????????????????

(x-y)(x-y)-yy