要答案！！
1. Jame bought X tarts, she ate 1/4 of them, then her brother and sister ate 7 tarts.
If 2 tarts were left, find the value of X.
2. Helen and Susan have a total of $40. If Helen has 4 times as much money as Susan,
how much money does each of them have?
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2006-10-17 5:24 am
回答 (6)
2006-10-17 5:30 am
✔ 最佳答案
1)the value of X(1-1/4)X - 7 = 2
(3/4)X - 7 = 2
4[(3/4)X - 7 ]= 2(4)
3X - 28 = 8
3X = 36
X = 12
therefore the value of X is 12.
2)Let $x be the number of money Helen has, that the number of money Susan has is $4x
x+4x = 40
5x = 40
x = 8
therefore Helen has$8. Susan has $ 32.
2006-10-17 6:12 am
1)
x-1/4x-7=2
x-1/4x=2+7
(1-1/4)x=9
3\4x=9
x=12
2)
$x=Helen
$y=Susan
x+y=40--1
x=4y --2
sub 2 to 1,
4y+y=40
5y=40
y=8
x=4y
x=4x8
x=32
x-1/4x-7=2
x-1/4x=2+7
(1-1/4)x=9
3\4x=9
x=12
2)
$x=Helen
$y=Susan
x+y=40--1
x=4y --2
sub 2 to 1,
4y+y=40
5y=40
y=8
x=4y
x=4x8
x=32
2006-10-17 6:00 am
sorry i dont understand your first question!!!
2) 4x+x =40 Helen=4x Susan=x
5x =40
x =40/5
x =8
so,Helen 4(8)=32 & Susan 1(8)=8
2) 4x+x =40 Helen=4x Susan=x
5x =40
x =40/5
x =8
so,Helen 4(8)=32 & Susan 1(8)=8
參考: my own opinion
2006-10-17 5:36 am
1. X=64
2. Helen=$20
Susan=$20
2. Helen=$20
Susan=$20
2006-10-17 5:29 am
1) X - [(1/4)* X + 7] = 2
X - 0.25X - 7 = 2
0.75X = 2 +7
0.75X = 9
X = 9 / 0.75
X = 12
2006-10-16 21:32:29 補充：
2) LET X AND 4X BE THE MONEY WHICH SUSAN AND HELEN HAS RESPECTIVELY.4X + X = 405X = 40X = 8THEREFORE, SUSAN HAS $8 AND HELEN HAS $32 .
X - 0.25X - 7 = 2
0.75X = 2 +7
0.75X = 9
X = 9 / 0.75
X = 12
2006-10-16 21:32:29 補充：
2) LET X AND 4X BE THE MONEY WHICH SUSAN AND HELEN HAS RESPECTIVELY.4X + X = 405X = 40X = 8THEREFORE, SUSAN HAS $8 AND HELEN HAS $32 .
2006-10-17 5:27 am
1. X-1/4-7=2
2. a+4a=40
2. a+4a=40
收錄日期: 2021-04-13 16:09:23
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