指數求x的值

11^3x - 2 = 1
11^3x = 1+ 2
11^3x = 3
log (11^3x) = log 3
3x * log (11) = log 3
3x = log 3 / log 11
3x = 0.458
x = 0.153

3^a乘9^b = 3^x
(3^a)*(9^b) = 3^x
(3^a)*[(3^2)^b] = 3^x
(3^a)*(3^2b) = 3^x
3^(a+2b) = 3^x
log [3^(a+2b)] = log (3^x)
(a+2b)*log 3 = x*log 3
a+2b = x
x = a + 2b

2 + x^-3 = 1
x^-3 = 1 - 2
x^-3 = -1
1 / x^3 = -1
x^3 = -1
x = -1

8乘5^x - 1
= 8 * 5^x - 1
please state this question clearly

Solution:

(a)
11^3x-2=1
11^3x=1+2
11^3x=3
log11^3x=log3
3xlog11=log3
x=log3 / (3 log11)
x=0.1527

(b)
3^a乘9^b=3^x
3^a乘3^2b=3^x
3^ (a + 2b) =3^x
a + 2b = x
x = a + 2b

©
2+x^-3=1
x^-3 = 1 - 2
x^-3= -1
1 / (x^3) = -1
1 / -1 = (x^3)
x^3= -1
x^3= (-1)^3
x = -1

(d)
8乘5^x-1 = 1000
8乘5^x = 1000 + 1
8乘5^x = 1001
5^x = 1001 / 8
log (5^x) = log(1001 / 8)
x log 5 = log 1001 – log 8
x = (log 1001 – log 8) / log 5
x = 3..0006

x=0/11110
maybe