f.3maths一條

2006-10-16 2:32 am
the speed of abullet train is measure as 7.2km/h,correct to the nearest x km/h.Given the percentage error in the measurement is 1又18分之7%
a).Find X
b).Between what limits does the true speed of the bulet train lie?

回答 (2)

2006-10-16 4:06 am
✔ 最佳答案
a) x= 7.2*(1又18分之7%)
= 7.2*(25/7%)
= 0.257km/h

b) lower limit = 7.2-0.257 = 6.943km/h
upper limit = 7.2+0.257 = 7.457km/h

2006-10-23 16:30:24 補充:
更正:1又18分之7% = 25 / 18 % ( not (25/7%)) (sorry !!!!) then x = 7.2*(25/18)% = 0.1 km/hb) lower limit = 7.2 - 0.1 = 7.1 km/h upper limit = 7.2 0.1 = 7.3 km/htherefore the range of speed is between 7.1 to 7.3 km/h
2006-10-18 1:29 am
∵maximum percentage error = maximum absolute error / measured value×100%
∴maximum absolute error = measured value×maximum absolute error

a) the maximum absolute error
=7.2km/h×1 / 7 / 18%
=10km/h
∵maximum absoulte error = 1 / 2×correct to the nearest X
∴correct to the nearest X = maximum absoulte error×2
Find X
=10km/h×2
=20km/h

b).upper limit = (10+ 7.2) km/h = 17.2 km/h
lower limit = (10﹣7.2) km/h = 2.8 km/h
==============================================
upper limit = measured value + maximum absoulte error
lower limit = measured value﹣maximum absoulte error
上限 = 量度值+ 最大絕對誤差
下限 = 量度值﹣最大絕對誤差
==============================================
maximum absoulte error = 最大絕對誤差
maximum percentage error = 最大百分誤差
upper limit = 上限
lower limit = 下限
參考: The form three maths book


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