7b+18-5b-8/b
a) no. of term
b) constant terms
F.1 Maths!!!!!!!!!!!!!極急!!!!!!!!!!!!!!
2006-10-16 1:49 am
回答 (7)
2006-10-16 1:52 am
✔ 最佳答案
a) no. of term →2b) constant terms →1
2006-10-16 2:30 am
7b+18-5b-8/b
=7b-5b+18-8/b
=2b+18-8/b
so a)according to the answer,the answer have 3 terms,the constant term=18
=7b-5b+18-8/b
=2b+18-8/b
so a)according to the answer,the answer have 3 terms,the constant term=18
參考: me
2006-10-16 2:21 am
7b+18-5b-8/b
=7b-5b+18-8/b
=2b+18-8/b
a)according to the answer,the answer have 3 terms,the constant term=18
=7b-5b+18-8/b
=2b+18-8/b
a)according to the answer,the answer have 3 terms,the constant term=18
2006-10-16 1:54 am
a) 7b-5b=2b is one of the term
18 is one term
-8/b is one term
SO, 3 terms
b) 18
18 is one term
-8/b is one term
SO, 3 terms
b) 18
2006-10-16 1:53 am
7b+18-5b-8/b
=18+2b-8/b
a) no. of term =3
b) constant terms =18
2006-10-15 17:54:26 補充：
我的理解是 no. of constant terms=1 lor
=18+2b-8/b
a) no. of term =3
b) constant terms =18
2006-10-15 17:54:26 補充：
我的理解是 no. of constant terms=1 lor
2006-10-16 1:52 am
13b+18-8/b
2006-10-15 17:53:37 補充：
a)=2b)=1
2006-10-15 17:53:37 補充：
a)=2b)=1
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