a^2 - b^2 + 2ab - 2ab^2
要有STEP;THX;,,,
^後面個數字係幾次方
MATHS"
2006-10-15 4:35 am
回答 (2)
2006-10-15 4:38 am
✔ 最佳答案
a^2 - b^2 + 2ab - 2ab^2= (a^2 - b^2) + 2ab(b - a)
= (a + b)(a - b) + 2ab[-(a - b)]
= (a + b)(a - b) - 2ab(a - b)
= (a - b)(a + b - 2ab)
2006-10-16 12:40 am
a^2 - b^2 + 2ab - 2ab^2
= (a^2 - b^2) + 2ab(1 - b)
= (a + b)(a - b) + 2ab(1-b)
= (a^2 - b^2) + 2ab(1 - b)
= (a + b)(a - b) + 2ab(1-b)
參考: maths
收錄日期: 2021-04-27 14:55:14
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