function
2006-10-14 11:11 pm
if h(x)=7x^2-10x-12 and k(x)=(-5/3)x,find the values of x such that h(x)=k(7x+6)
回答 (3)
2006-10-14 11:16 pm
✔ 最佳答案
if h(x)=7x^2-10x-12 and k(x)=(-5/3)x,find the values of x such that h(x)=k(7x+6) h(x)=7x^2-10x-12
k(x)=(-5/3)x
h(x)=k(7x+6)
7x^2-10x-12=(-5/3)(7x+6)
21x^2-30x-36=-35x-30
21x^2+5x-6=0
(3x+2)(7x-3)=0
x=-2/3 or x=3/7
2006-10-14 11:19 pm
if h(x)=7x2-10x-12 and k(x)=(-5/3)x,find the values of x such that h(x)=k(7x+6)
7x2-10x-12=(-5/3)(7x+6)
21x2-30x-36=-5(7x+6)
21x2-30x-36=-35x+-30
21x2 + 5x – 6= 0
(7x – 3)(3x + 2) = 0
x = 3/7 或 x = -2/3
7x2-10x-12=(-5/3)(7x+6)
21x2-30x-36=-5(7x+6)
21x2-30x-36=-35x+-30
21x2 + 5x – 6= 0
(7x – 3)(3x + 2) = 0
x = 3/7 或 x = -2/3
2006-10-14 11:16 pm
h(x) = k(7x + 6)
7x^2 - 10x - 12 = (-5 / 3)(7x + 6)
3(7x^2 - 10x - 12) = -5(7x + 6)
21x^2 - 30x - 36 = -35x - 30
21x^2 + 5x - 6 = 0
(3x + 2)(7x - 3) = 0
x= -2 / 3 or 3 / 7
7x^2 - 10x - 12 = (-5 / 3)(7x + 6)
3(7x^2 - 10x - 12) = -5(7x + 6)
21x^2 - 30x - 36 = -35x - 30
21x^2 + 5x - 6 = 0
(3x + 2)(7x - 3) = 0
x= -2 / 3 or 3 / 7
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