7K-(9K-16)=14-(19-K) 求K (請詳細解答)
2/3(3b+2)-1/6(3b-1)=-1/1/2 求B (請詳細解答)
數學-代數
2006-10-14 5:39 am
回答 (6)
2006-10-14 5:50 am
✔ 最佳答案
7K-(9K-16)=14-(19-K) 求K16-2K=K-5
3K=21
K=7
2/3(3b+2)-1/6(3b-1)=-1/1/2 求B
2b+4/3-1/2b+1/6=-1/1/2
1/1/2b=-3
b=-2
你對下個ans.~睇下啱唔啱
希望幫到你 ^ v ^
2006-10-14 5:59 am
7K-(9K-16)=14-(19-K)
7K-9K+16=14-19+K
7K-9K-K=14-19-16
-3K=-21
K=7
2/3(3b+2)-1/6(3b-1)=-1/1/2
2b+4/3-b/2+1/6=-2
2b-b/2=-2-4/3-1/6
12b-3b=-12-8-1
9b=-21
b=-21/9
b=-7/3
7K-9K+16=14-19+K
7K-9K-K=14-19-16
-3K=-21
K=7
2/3(3b+2)-1/6(3b-1)=-1/1/2
2b+4/3-b/2+1/6=-2
2b-b/2=-2-4/3-1/6
12b-3b=-12-8-1
9b=-21
b=-21/9
b=-7/3
2006-10-14 5:48 am
1.
7K-(9K-16)=14-(19-K)
7K-9K+16 =14-19+K
7K-9K+16+19=14-19+K+19
-2K+35-14=14+K-14
-2K+21=K
3K/3=21/3
K=7
2.
不懂
7K-(9K-16)=14-(19-K)
7K-9K+16 =14-19+K
7K-9K+16+19=14-19+K+19
-2K+35-14=14+K-14
-2K+21=K
3K/3=21/3
K=7
2.
不懂
2006-10-14 5:46 am
7K-(9K-16)=14-(19-K)
7K-9K+16=14-19+K
-2k-K=-5-16
-3K=-21
K=7
第二題個右邊係-1除1/2定-1/1除2 ?
左邊係2除3(3b+2)定係2(3b+2)除3??
7K-9K+16=14-19+K
-2k-K=-5-16
-3K=-21
K=7
第二題個右邊係-1除1/2定-1/1除2 ?
左邊係2除3(3b+2)定係2(3b+2)除3??
2006-10-14 5:44 am
7K-(9K-16)=14-(19-K)
7K-9K+16=14-19+K
-2K+16= -5+K
21=3K
K=9
2006-10-13 21:45:07 補充：
K=7吾係=9
7K-9K+16=14-19+K
-2K+16= -5+K
21=3K
K=9
2006-10-13 21:45:07 補充：
K=7吾係=9
2006-10-14 5:44 am
7K-(9K-16)=14-(19-K)
7K-9K+16=14-19+K
-2K + 16 = -5+K
-2K-K = -5-16
-3K = -21
K = 7
2/3(3b+2)-1/6(3b-1)=-1/1/2??
疑問→(3b+2)係乘去分子定係分母呢
仲有，(3b-1)又係乘寺分子定係分母呢
你補充番先啦
7K-9K+16=14-19+K
-2K + 16 = -5+K
-2K-K = -5-16
-3K = -21
K = 7
2/3(3b+2)-1/6(3b-1)=-1/1/2??
疑問→(3b+2)係乘去分子定係分母呢
仲有，(3b-1)又係乘寺分子定係分母呢
你補充番先啦
收錄日期: 2021-04-18 20:44:29
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https://hk.answers.yahoo.com/question/index?qid=20061013000051KK04286