數學-代數

7K-(9K-16)=14-(19-K) 求K
16-2K=K-5
3K=21
K=7

2/3(3b+2)-1/6(3b-1)=-1/1/2 求B
2b+4/3-1/2b+1/6=-1/1/2
1/1/2b=-3
b=-2

你對下個ans.~睇下啱唔啱
希望幫到你 ^ v ^

7K-(9K-16)=14-(19-K)
7K-9K+16=14-19+K
7K-9K-K=14-19-16
-3K=-21
K=7



2/3(3b+2)-1/6(3b-1)=-1/1/2
2b+4/3-b/2+1/6=-2
2b-b/2=-2-4/3-1/6
12b-3b=-12-8-1
9b=-21
b=-21/9
b=-7/3

1.
7K-(9K-16)=14-(19-K)
7K-9K+16 =14-19+K
7K-9K+16+19=14-19+K+19
-2K+35-14=14+K-14
-2K+21=K
3K/3=21/3
K=7
2.
不懂

7K-(9K-16)=14-(19-K)
7K-9K+16=14-19+K
-2k-K=-5-16
-3K=-21
K=7

第二題個右邊係-1除1/2定-1/1除2 ?
左邊係2除3(3b+2)定係2(3b+2)除3??

7K-(9K-16)=14-(19-K)
7K-9K+16=14-19+K
-2K+16= -5+K
21=3K
K=9

2006-10-13 21:45:07 補充：
K=7吾係=9

7K-(9K-16)=14-(19-K)
7K-9K+16=14-19+K
-2K + 16 = -5+K
-2K-K = -5-16
-3K = -21
K = 7

2/3(3b+2)-1/6(3b-1)=-1/1/2??
疑問→(3b+2)係乘去分子定係分母呢
仲有，(3b-1)又係乘寺分子定係分母呢

你補充番先啦