I know that the critical points are x = 2 and -3.
BUT should x = 1 also be another critical point?
Find the "critical points" of dy/dx = [(x-2)(x+3)]/[x-1]?
2006-09-26 4:38 pm
回答 (3)
2006-09-26 4:48 pm
✔ 最佳答案
yes at x=1 you get an asymptote
2006-09-26 4:47 pm
You could consider x = 1 a critical point - this equation graphed would have a 'gap' at x = 1, so it could hypothetically be called a 'critical point'
2006-09-26 4:42 pm
no, beacuse if you fill in x=1, then you'll have to divide by 0 and that's impossible, so critical points are x=2 and x=-3 AND x DOES NOT equal 1!!
收錄日期: 2021-04-23 12:47:52
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