I've tried implicit differentiation, ie.
d/dx [cos (sec (xy))] = d/dx (cos x sec y)
For right-hand-side,
d/dx (cos x sec y)
= [(d/dx cos x) (sec y)] + [(cos x) (dy/dx d/dy sec y)]
= [(-sin x) (sec y)] + [(cos x) (sec y) (tan y) (dy/dx)]
For left-hand-side,
d/dx [cos (sec (xy))]
"and I have no idea to go on..."
Please help, thanks a lot!
Derivatives of trigonometric functions: Find the derivative dy/dx for cos [sec (xy)] = cos x sec y?
2006-09-05 8:25 am
回答 (1)
2006-09-05 7:14 pm
✔ 最佳答案
If you can't get the answer here try asking on allexperts.com under homework help/mathmatics\calculus. Hope this helps.
收錄日期: 2021-04-25 13:06:04
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